Cron file help

[rednspirited]

i have been searching the site for info but after hours of reading i decided to make this post. i have tried different ways but cant seem to make my cron files to work.  i am only posting the minute file cause its the shortest and the code line is pretty much the same for each. any help i will be greatful for . thank you 

 

require_once(dirname(__FILE__) . "/../mysqli.php");
$cron_code = '* * * * * curl public_html/cron_minute.php?code=672bb9f5a0b168da99fbbf74980175ecd';
if ($argc == 2) {
    if ($argv[1] != $cron_code) {
        exit;
    }
} else if (!isset($_GET['code']) || $_GET['code'] !== $cron_code) {
    exit;
}
mysqli_query("UPDATE users SET hospital=hospital-1 WHERE hospital>0", $c);

 

[Crow]

No clue just here to stalk

 

[AdamHull]

* * * * * curl public_html/cron_minute.php?code=672bb9f5a0b168da99fbbf74980175ecd

This needs adding to your crontab you may have to add other file directories to the beging but there should be documentation in your crontab for this

*Edit how ever you formatted that code has broken the code section and won't let me post it as code 

[rednspirited]

thanks i will try that and see what happens 

still didnt work is there somethingelse i should add?

[Magictallguy]

You've passed a cron command to a variable that shouldn't be there.
Change your $cron_code var to hold, funnily enough, your cron's code (an override token that allows it to run).

$cron_code = '672bb9f5a0b168da99fbbf74980175ecd';

You may also wish to generate a new cron token as that one is now public - note that, if you do, you will need to update the cron commands with the new token too

[rednspirited]

if my dataase is named battlefo_battlefo************* and my line reads like this 

php /home/battlefo/public_html/crons/cron_fivemins.php    in my cornsjob 

Should it read battlefo_battlefo************ in the code line?

[Magictallguy]

You haven't passed the cron token to your command either.

So, the top of your cron file (using the snippet you posted as reference)

require_once dirname(__DIR__).'/mysqli.php';
$cron_code = '672bb9f5a0b168da99fbbf74980175ecd';
if ($argc == 2) {
    if ($argv[1] != $cron_code) {
        exit;
    }
} else if (!isset($_GET['code']) || $_GET['code'] !== $cron_code) {
    exit;
}

And your command should be

php /home/battlefo/public_html/crons/cron_fivemins.php code=672bb9f5a0b168da99fbbf74980175ecd

 

[rednspirited]

1 hour ago, Magictallguy said:

You haven't passed the cron token to your command either.

So, the top of your cron file (using the snippet you posted as reference)

require_once dirname(__DIR__).'/mysqli.php'; $cron_code = '672bb9f5a0b168da99fbbf74980175ecd'; if ($argc == 2) { if ($argv[1] != $cron_code) { exit; } } else if (!isset($_GET['code']) || $_GET['code'] !== $cron_code) { exit; }

require_once dirname(__DIR__).'/mysqli.php';
$cron_code = '672bb9f5a0b168da99fbbf74980175ecd';
if ($argc == 2) {
    if ($argv[1] != $cron_code) {
        exit;
    }
} else if (!isset($_GET['code']) || $_GET['code'] !== $cron_code) {
    exit;
}

And your command should be

php /home/battlefo/public_html/crons/cron_fivemins.php code=672bb9f5a0b168da99fbbf74980175ecd

php /home/battlefo/public_html/crons/cron_fivemins.php code=672bb9f5a0b168da99fbbf74980175ecd

 

That's how it reads but they dont work

[Magictallguy]

Alright, let's try a slightly different method.
Replace

if ($argc == 2) {
    if ($argv[1] != $cron_code) {
        exit;
    }
} else if (!isset($_GET['code']) || $_GET['code'] !== $cron_code) {
    exit;
}

with

if (isset($argv)) {
    $args = parse_str($argv[1], $param);
    $_GET['code'] = $param['code'];
}
if(!array_key_exists('code', $_GET) or $_GET['code'] != $cron_code) {
    exit;
}

 

[rednspirited]

Got it up and running thank you so much for the help I couldn't have figured it out with out your help 

[Magictallguy]

Happy to help, glad to hear you're up and running ^.^

[rednspirited]

Now on to the next ? thanks