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Posted

Been away from this for months but needed to make a quick script for something and been tripped up on day 1 stuff. Anyone know why this would be constantly showing up as a positive match? I want it to fail and give the error message if all 4 numbers match another entry with those exact same 4 numbers. Even if only 3 numbers of 4 match, the script should progress, but its always showing a match. I know its something simple, just can't see it :s

 

$q=mysql_query("SELECT * FROM tickets WHERE name='{$_POST['name']}'");
		while($c=mysql_fetch_assoc($q)) {
		if(($_POST['no1'] == $c['no1'] || $c['no2'] || $c['no3'] || $c['no4']) && ($_POST['no2'] == $c['no1'] || $c['no2'] || $c['no3'] || $c['no4']) && ($_POST['no3'] == $c['no1'] || $c['no2'] || $c['no3'] || $c['no4']) && ($_POST['no4'] == $c['no1'] || $c['no2'] || $c['no3'] || $c['no4']))
		{
		echo "This ticket already exists.<br><a href='add.php'>Back</a>";
		exit;
		}
		}
Posted (edited)

Um, try this:

 

$q=mysql_query("SELECT * FROM tickets WHERE name='{$_POST['name']}'");
while($c=mysql_fetch_assoc($q)) {
  if( in_array($_POST['no1'], array_values($c)) AND in_array($_POST['no2'], array_values($c)) AND in_array($_POST['c3'], array_values($c)) AND in_array($_POST['no4'], array_values($c)) {
        echo "This ticket already exists. <a href='add.php'>Back</a>";
        break;
   }
}
Edited by sniko
  • 4 weeks later...
Posted

@Bineye: Why do you want to do this ?

Let the DB deside this: if Query: INSERT ..... INTO TICKETS gives a key error saying the key already exists. Than you know.

Also you can just say: "Insert this if not exists, but UPDATE if doesn exists"

 

Now your doing a SELECT statement that will echo some text, and does nothing...

Just make code that does SOMETHING (hopefully logical) and if that doesn't work for some reason like: "Ticket already exists".

Throw a exception, like Throw New TicketProblem(SQL_UPDATE, "Ticket already Exists")

 

Happy Hacking: Roger

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