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Ranking System idea


POG1
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im not to sure hot to create a ranking system but this is what im thinking of...

 

<?
function game_rank($ir)
{
$rank=0;

if($ir[level] =< 5) { $rank++; }
if($ir[level] =< 10) { $rank++; }
if($ir[level] =< 15) { $rank++; }
if($ir[level] =< 20) { $rank++; }
if($ir[level] =< 25) { $rank++; }
if($ir[level] =< 30) { $rank++; }

if($ir[networth] =< 500) { $rank++; }

$rank_array = array('#1', '#2', '#3', '#4','#5', '#6', '#7');

if($rank != $ir[rank]) {
$query = "UPDATE users SET rank = ".$rank_array." WHERE userid = ".$userid;
mysql_query($query);
}
?>

 

any help?

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Re: Ranking System idea

you're going to want to store that rank as a number, and not with the # symbol attached to it.

 

if($rank != $ir[rank]) {

when you compare $rank to #5 for example, that #5 will become a 0 for all intents and purposes, as it will be converted to an integer.

so just store $rank in that query ;)

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Re: Ranking System idea

 

when you compare $rank to #5 for example, that #5 will become a 0 for all intents and purposes, as it will be converted to an integer.

it compares the $rank variable not $rank_array, im not verry good with arrays so it probly wont work anyway lol

i was thinking of taking the array out and just putting tan array on the output,i dunno if it would work...

$ir[rank] = array('1'=>'#1 noob','2'=>'#2 ...','3'=>'#3','4'=>'#4','5'=>'#5','6'=>'#6','7'=>'#7');

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Re: Ranking System idea

 

when you compare $rank to #5 for example, that #5 will become a 0 for all intents and purposes, as it will be converted to an integer.

it compares the $rank variable not $rank_array, im not verry good with arrays so it probly wont work anyway lol

 

But look at how your query is:

$query = "UPDATE users SET rank = ".$rank_array." WHERE userid = ".$userid;

 

Number one, you're attempting to store the rank as #3 or whatever my rank would be, so the next time you run the script, your comparison fails. Believe it or not, I'm 110% certain of that fact.

Even worse is the fact that your intentions of storing the #5 in the database table will not work in the first place and will throw a mysql error. You would know this if you had added to this line:

mysql_query($query) or echo mysql_error();
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Re: Ranking System idea

 

when you compare $rank to #5 for example, that #5 will become a 0 for all intents and purposes, as it will be converted to an integer.

it compares the $rank variable not $rank_array, im not verry good with arrays so it probly wont work anyway lol

 

But look at how your query is:

$query = "UPDATE users SET rank = ".$rank_array." WHERE userid = ".$userid;

 

Number one, you're attempting to store the rank as #3 or whatever my rank would be, so the next time you run the script, your comparison fails. Believe it or not, I'm 110% certain of that fact.

Even worse is the fact that your intentions of storing the #5 in the database table will not work in the first place and will throw a mysql error. You would know this if you had added to this line:

mysql_query($query) or echo mysql_error();

 

but the rank field wouldn't be a integer so it would store the value #

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Re: Ranking System idea

a bit plain still and i dunno if its the best way to be done but here is what i got now and it works

 

<?php
function gameRank()
{
global $ir,$userid,$c;

$rank=0;
$net=1000;
while($ir[level] >=5) { $rank++; $ir[level]=$ir[level]-5; }
while($ir[networth] > 1200) { $rank++; $net=$net*$ir[networth]/2; $ir[networth]=$ir[networth]-$net; }

if($rank != $ir[rank]) 
{
	$query = "UPDATE users SET rank = ".$rank." WHERE userid = ".$userid;
	mysql_query($query) or die(mysql_error());
}
}
?>
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Re: Ranking System idea

 

 

but the rank field wouldn't be a integer so it would store the value #

 

Jeezus christ, when you do the comparison if($rank != $ir[rank])

You're going to be comparing an INTEGER to a STRING

That's what I've been trying to tell you, you need to just go with $rank, and only use that array when you wanna show someone their rank.

______________________

Anyways, that's a moot point as you say you have it working. I see you did go with $rank in the query in the end.

You're welcome.

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