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Please help A.S.A.P


jimmytubbs

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EDITED:

hi

on my newspaper i get this

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 12 in /home/*****/public_html if(!$result) { $result=$this->result; }

return mysql_result($result, 0, 0) on line 94

and here the code

 function fetch_single($result=0)
{
if(!$result) { $result=$this->result; }
return mysql_result($result, 0, 0);
}

 

cheers

jimmytubbs

p.s i am trying to learn how to code

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Re: Please help A.S.A.P

Please also post what the value of the variable $cnt is, and if it refers to any other variable, please also post it.

The error message means that the query supplied to the mysql_query function is invalid, and teh function mysql_result is giving an error because it has an invalid resource.

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