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Posted

It seems i can run the following query on mySQL but i am struggling to get it to work with the PHP.

I am not recieving any error message as such, but my results = 'Resource id #4'

 

	$TimeDiff = "SELECT TIMEDIFF('2007-11-17 17:10:19','2007-11-17 17:07:05')";
$DownTime =  mysql_query($TimeDiff)
or die (mysql_error());

 

I think I need a mysql_fetch, but I am not sure what to use since this query is not coming from a table, any help on this guys.

Maybe some other function could help. For example list() , would work in theory. Well i hope you guys can help. Thanks in advance,

¬LK

  • 2 weeks later...
Posted

Re: Mysql/PHP problem

$TimeDiff = "SELECT TIMEDIFF('2007-11-17 17:10:19','2007-11-17 17:07:05')";

$DownTime = mysql_query($TimeDiff) or die (mysql_error());

If you take that, and then do:

echo $DownTime;

you are echoing a memory resource locator. In other words, that variable simply holds the "directions" to a place in memory.

so, you would need to do msyql_fetch_array or mysql_fetch_row

which ever one you choose does not matter, especially if you use list, which I highly recommend in most situations.

list($mytime) = mysql_fetch_array($DownTime);

echo $mytime; // and you're get the results you expect.

Posted

Re: Mysql/PHP problem

Well thank you for re-assuring me that list() function works good for this exact situation.

 

$query = "SELECT TIMEDIFF('2007-11-17 17:10:19','2007-11-17 17:07:05')";

$results = mysql_query($query);

list($timediff) = mysql_fetch_array($results);

echo $timediff; // 00:03:14

Thank you Floydian... :)

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