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Surrender not able to be accepted.


Aderik

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Hello again!

I'm running into another problem, when ever someone goes to accept a surrender they are met with a query error.

 

function gang_staff_viewsurrenders()
{
global $db,$ir,$c,$userid,$gangdata;
if(!isset($_POST['subm']))
{
print "<form action='yourcoalition.php?action=staff&act2=viewsurrenders' method='post'>
Choose who to accept the surrender from.

<input type='hidden' name='subm' value='submit' />
Gang: <select name='sur' type='dropdown'>";
$wq=$db->query("SELECT s.*,w.* FROM surrenders s LEFT JOIN gangwars w ON s.surWAR=w.warID WHERE surTO={$ir['gang']}");

while($r=$db->fetch_row($wq))
{
if($gangdata['gangID'] == $r['warDECLARER']) { $w="You";$f="warDECLARED"; } else { $w="Them";$f="warDECLARER"; }
$ggq=$db->query("SELECT * FROM gangs WHERE gangID=".$r[$f]);
$them=$db->fetch_row($ggq);
print "<option value='{$r['surID']}'>War vs. {$them['gangNAME']} (Msg: {$r['surMSG']})</option>";
}
print "</select>
<input type='submit' value='Accept Surrender' /></form>";
}
else
{
$_POST['sur'] = abs((int) $_POST['sur']);
$q=$db->query("SELECT surWAR FROM surrenders WHERE surID={$_POST['sur']}");
$xx = $db->fetch_row($q);
$_POST['war'] = abs((int) $xx);
$wq=$db->query("SELECT * FROM gangwars WHERE warID={$_POST['war']}"); //*This is the code with the error*//
$r=$db->fetch_row($wq);
if($gangdata['gangID'] == $r['warDECLARER']) { $f="warDECLARED"; } else { $f="warDECLARER"; }
$db->query("DELETE FROM surrenders WHERE surID={$_POST['sur']}");
$db->query("DELETE FROM gangwars WHERE warID={$_POST['war']}");
$ggq=$db->query("SELECT * FROM gangs WHERE gangID=".$r[$f]);
$them=$db->fetch_row($ggq);
$event=str_replace("'","''","[url='coalition.php?action=view&ID={$ir[']{$gangdata['gangNAME']}[/url] have accepted the surrender from [url='coalition.php?action=view&ID={$them[']{$them['gangNAME']}[/url], the war is over!");
$db->query("INSERT INTO gangevents VALUES('',{$ir['gang']},unix_timestamp(),'$event') , ('',".$r[$f].",unix_timestamp(),'$event')");
print "You have accepted surrender, the war is over.";
}
}

 

This is the function and below is the error.

Quote (My Game)

QUERY ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

Query was SELECT * FROM gangs WHERE gangID=

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function gang_staff_viewsurrenders()
{
global $db,$ir,$c,$userid,$gangdata;
if(!isset($_POST['subm']))
{
print "<form action='yourcoalition.php?action=staff&act2=viewsurrenders' method='post'>
Choose who to accept the surrender from.

<input type='hidden' name='subm' value='submit' />
Gang: <select name='sur' type='dropdown'>";
$wq=$db->query("SELECT s.*,w.* FROM surrenders s LEFT JOIN gangwars w ON s.surWAR=w.warID WHERE surTO={$ir['gang']}");

while($r=$db->fetch_row($wq))
{
if($gangdata['gangID'] == $r['warDECLARER']) { $w="You";$f="warDECLARED"; } else { $w="Them";$f="warDECLARER"; }
$ggq=$db->query("SELECT * FROM gangs WHERE gangID=".$r[$f]);
$them=$db->fetch_row($ggq);
print "<option value='{$r['surID']}'>War vs. {$them['gangNAME']} (Msg: {$r['surMSG']})</option>";
}
print "</select>
<input type='submit' value='Accept Surrender' /></form>";
}
else
{
$_POST['sur'] = abs((int) $_POST['sur']);
$q=$db->query("SELECT surWAR FROM surrenders WHERE surID={$_POST['sur']}");
$xx = $db->fetch_row($q);
$_POST['war'] = abs((int) $xx);
$wq=$db->query("SELECT * FROM gangwars WHERE warID={$_POST['war']}"); //*This is the code with the error*//
$r=$db->fetch_row($wq);
$db->query("DELETE FROM surrenders WHERE surID={$_POST['sur']}");
$db->query("DELETE FROM gangwars WHERE warID={$_POST['war']}");
if($gangdata['gangID'] == $r['warDECLARER'])
{
$ggq=$db->query("SELECT * FROM gangs WHERE gangID={$r['warDECLARED']}");
}
else
{
$ggq=$db->query("SELECT * FROM gangs WHERE gangID={$r['warDECLARER']}");
}
$them=$db->fetch_row($ggq);
$event=str_replace("'","''","[url='coalition.php?action=view&ID={$ir[']{$gangdata['gangNAME']}[/url] have accepted the surrender from [url='coalition.php?action=view&ID={$them[']{$them['gangNAME']}[/url], the war is over!");
$db->query("INSERT INTO gangevents VALUES('',{$ir['gang']},unix_timestamp(),'$event') , ('',".$r[$f].",unix_timestamp(),'$event')");
print "You have accepted surrender, the war is over.";
}
}

 

It is pretty wierd the way it is set up... But that should work.

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The code Kieran posted got me the same error result. And it's weird? I dunno... >_< I can't figure it out for the life of me.

Actually, using that code and trying to accept got me the error, but I don't have the surrender in the database anymore... I'll run some more tests.

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