Mark F Posted June 13, 2008 Posted June 13, 2008 Hello Everyone, I wish to display the name of my gang on my index page. I know that I have to add the following: if($r['gang']) { print "[url='gangs.php?action=view&ID={$r[']{$r['gangNAME']}[/url]"; } else { print "N/A"; } Though how do I change the following code so I only have what I need?: include "globals.php"; $_GET['u'] = abs((int) $_GET['u']); if(!$_GET['u']) { print "Invalid use of file"; } else { $q=$db->query("SELECT u.*,us.*,c.*,h.*,g.*,f.* FROM users u LEFT JOIN userstats us ON u.userid=us.userid LEFT JOIN cities c ON u.location=c.cityid LEFT JOIN houses h ON u.maxwill=h.hWILL LEFT JOIN gangs g ON g.gangID=u.gang LEFT JOIN fedjail f ON f.fed_userid=u.userid WHERE u.userid={$_GET['u']}"); Quote
Mark F Posted June 13, 2008 Author Posted June 13, 2008 Re: Help with silly problem, displaying gangs name. or it might just be easier for me to ask How do I display peoples gang names on the index page, lol. Quote
Halo Posted June 17, 2008 Posted June 17, 2008 Re: Display Gangs Name??? Add this to were the queries are: $wq=$db->query("SELECT * FROM gangwars where warDECLARER={$ir['gang']} or warDECLARED={$ir['gang']}"); $gq=$db->query("SELECT * FROM gangs WHERE gangID={$_GET['ID']}"); $gangdata=$db->fetch_row($gq); $gq=$db->query("SELECT g.*,oc.* FROM gangs g LEFT JOIN orgcrimes oc ON g.gangCRIME=oc.ocID WHERE g.gangID={$ir['gang']}"); $gangdata=$db->fetch_row($gq); Then add somewhere in Index.php: if($ir['gang']) { print " <u>Gang Info</u> Your Gang: [url='gangs.php?action=view&ID={$ir[']<font color=green>{$ir['gangNAME']} ({$ir['gangID']})</font>[/url] Your Gang Wars: <font color=red>".$db->num_rows($wq)." Wars</font> Your Gang Respect: {$ir['gangRESPECT']} "; } else { print "<u>Gang Info</u> Your not in a gang "; } Just thought of it, might not work but its worth a shot Quote
Mark F Posted August 16, 2008 Author Posted August 16, 2008 Re: Display Gangs Name??? I couldn't get it to work, I think that it had something to do with {$_GET['ID']} in the queries. Quote
Tonka Posted August 16, 2008 Posted August 16, 2008 Re: Display Gangs Name??? here is what i use and it works fine $q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.userid=$userid"); $g=$db->fetch_row($q); [b]Gang:[/b] "; if($g['gang']) { echo "[url='gangs.php?action=view&ID={$g[']{$g['gangNAME']}[/url] "; } else { echo "N/A "; } Quote
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