Mark F Posted June 6, 2008 Share Posted June 6, 2008 I am trying to install 'Marriage Pro', though I keep getting this error after I insert the code into index.php Parse error: syntax error, unexpected $end in /home/marfur93/public_html/index3.php on line 74 Does anyone know why this is? On line 74 in index.php it just says ?> Quote Link to comment Share on other sites More sharing options...
Mark F Posted June 6, 2008 Author Share Posted June 6, 2008 Re: Help with Syntax Error P.S. I get the error message when I add the following sode to my index.php $mq=mysql_query("SELECT * FROM `marriages` WHERE (`marriage_to` = '{$userid}') OR (`marriage_from` = '{$userid}')",$c); if(mysql_num_rows($mq)) { $mr=mysql_fetch_array($mq); if($mr['marriage_from'] == $userid) { $user=$mr['marriage_to']; } else { $user=$mr['marriage_from']; } $get_U=mysql_query("SELECT * FROM users WHERE userid=$user",$c); $gr=mysql_fetch_array($get_U); Quote Link to comment Share on other sites More sharing options...
Tezza` Posted June 6, 2008 Share Posted June 6, 2008 Re: Help with Syntax Error I am trying to install 'Marriage Pro', though I keep getting this error after I insert the code into index.php Parse error: syntax error, unexpected $end in /home/marfur93/public_html/index3.php on line 74 Does anyone know why this is? On line 74 in index.php it just says ?> Try putting a } bwfore you ?> Quote Link to comment Share on other sites More sharing options...
Mark F Posted June 6, 2008 Author Share Posted June 6, 2008 Re: Help with Syntax Error Thanks for your help, though it now says the following: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/marfur93/public_html/index3.php on line 10 Here is the code with line numbers: 09 $mq=mysql_query("SELECT * FROM `marriages` WHERE (`marriage_to` = '{$userid}') OR (`marriage_from` = '{$userid}')",$c); 10 if(mysql_num_rows($mq)) 11 { 12 $mr=mysql_fetch_array($mq); 13 if($mr['marriage_from'] == $userid) { $user=$mr['marriage_to']; } else { $user=$mr['marriage_from']; } 14 $get_U=mysql_query("SELECT * FROM users WHERE userid=$user",$c); 15 $gr=mysql_fetch_array($get_U); Quote Link to comment Share on other sites More sharing options...
Tezza` Posted June 6, 2008 Share Posted June 6, 2008 Re: Help with Syntax Error change rows to array i think Quote Link to comment Share on other sites More sharing options...
Mark F Posted June 7, 2008 Author Share Posted June 7, 2008 Re: Help with Syntax Error Sorry that I am new to this, though what do you mean exactly? Quote Link to comment Share on other sites More sharing options...
Tezza` Posted June 7, 2008 Share Posted June 7, 2008 Re: Help with Syntax Error on line 10, change the word "rows" to "array" Quote Link to comment Share on other sites More sharing options...
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