Saberman Posted August 17, 2009 Posted August 17, 2009 i am try to select the userids house pic but i get an error $qn=$db->query("SELECT hsepics FROM houses where hsepics={$ir['hsepics']}"); $n=$db->fetch_row($qn); does anyone know what it is QUERY ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 Query was SELECT hsepics FROM houses where hsepics= Quote
CrazyT Posted August 17, 2009 Posted August 17, 2009 Re: house pic That is totally wrong. $house_picture = $db->fetch_single($db->query('SELECT `hsepic` FROM `houses` WHERE hWILL = '. $ir['maxwill'])); echo '<h3>House Picture</h3>[img=images/houses/'. $house_picture .'] '; Hope it helps... Quote
Saberman Posted August 17, 2009 Author Posted August 17, 2009 Re: house pic That is totally wrong. $house_picture = $db->fetch_single($db->query('SELECT `hsepic` FROM `houses` WHERE hWILL = '. $ir['maxwill'])); echo '<h3>House Picture</h3>[img=images/houses/'. $house_picture .'] '; Hope it helps... Thank you very very much CrazyT mate this works perfectly +1 Quote
CrazyT Posted August 17, 2009 Posted August 17, 2009 Re: house pic That is totally wrong. $house_picture = $db->fetch_single($db->query('SELECT `hsepic` FROM `houses` WHERE hWILL = '. $ir['maxwill'])); echo '<h3>House Picture</h3>[img=images/houses/'. $house_picture .'] '; Hope it helps... Thank you very very much CrazyT mate this works perfectly +1 No problem :) Quote
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