Re: Free 2 - Icons
I have a problem all i get is this:
(Array);
here i my codes:
style:
#icons { text-align:center; }
#icons img { padding:0 2px; }
Display:
$this->display_icons($ir);
Global_func:
function display_icons( $u, $i = array() )
{
if ($n = $u['new_announcements']) { $t = sprintf("%u New Announcement%s", $n, $n == 1 ? "" : "s"); $i[] = sprintf("[img=icons/announcements.png]", $t, $t); }
if ($y = $u['new_mail']) { $t = sprintf("%u New Mail%s", $y, $y == 1 ? "" : "s"); $i[] = sprintf("[img=icons/mail.png]", $t, $t); }
if ($n = $u['new_events']) { $t = sprintf("%u New Event%s", $n, $n == 1 ? "" : "s"); $i[] = sprintf("[img=icons/events.png]", $t, $t); }
if ($a = max($u['bankmoney'], 0) + max($u['cybermoney'], 0)) { $fa = "$" . number_format($a) . " Banked"; $i[] = sprintf("[img=icons/bank.png]", $fa, $fa); }
if ($z = $u['jobrank']) { $rs = mysql_query(sprintf("SELECT CONCAT(\"Working as \", `jrNAME`, \" in \", `jDESC`) FROM `jobranks` LEFT JOIN `jobs` ON `jrJOB` = `jID` WHERE (`jrID` = %u)", $z)); $row = mysql_fetch_array($rs); mysql_free_result($rs); $i[] = sprintf("[img=icons/working.png]", $row[0], $row[0]); }
if (($p = $u['course']) && $u['cdays']) { $rs = mysql_query(sprintf("SELECT CONCAT(\"Studying \", `crName`) FROM `courses` WHERE (`crID` = %u)", $p)); $row = mysql_fetch_row($rs); mysql_free_result($rs); $i[] = sprintf("[img=icons/studying.png]", $row[0], $row[0]); }
if (count($i)) echo "<div id='icons'>" . implode("", $i) . "</div><hr />";
}
heres a link to a screenshot of the problem:
http://www.icons.crimsonville.com/prob/icons_mod.png